accessing multiple references

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1 comment

  • Rainer Grabowski

    Hi Martin,

    it can display. And you don't need a loop for that. You can get it as a string by adding .join() . Inbetween the brackets you can define a separator like "\n" for linebreaks between the elements:

     var textarray = @All of text field in B.join("\n")
    

    Instead of "\n" you can set any other separator like " " or "; "

    Rainer

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